( 𝑥 − 2 ) 2 𝑥 − 5 < 0 ${\displaystyle \frac{{\left(x-2\right)}^2}{x-5}<0}$

2 − 𝑥 < 0,25 ${\displaystyle 2^{-x}<\mathrm{0,25}}$

log 5 𝑥 > 1 ${\displaystyle {\log }_{5}x>1}$

( 𝑥 − 2 ) ( 𝑥 − 5 ) < 0 ${\displaystyle \left(x-2\right)\left(x-5\right)<0}$

𝑥 > 2 $x>2_{}^{}$

2 < 𝑥 < 5 $2<x<5_{}^{}$

𝑥 > 5 $x>5_{}^{}$

𝑥 < 2 $x<2_{}^{}$ или 2 < 𝑥 < 5 $2<x<5_{}^{}$