Найдите tg 𝛼 ${\displaystyle \mathrm{tg}\alpha }$ , если sin 𝛼 = 1 26 ‾ ‾ ‾ √ ${\displaystyle \sin \alpha =\frac{1}{\sqrt{26}}}$ и 90 ° < 𝛼 < 180 ° ${\displaystyle 90°<\alpha <180°}$ .