log 2 ( 𝑥 − 1 ) < 1 ${\displaystyle {\log }_2\left(x-1\right)<1^{}}$

3 − 2 𝑥 > 1 9 ${\displaystyle 3^{-2x}>{\frac{1}{9}}^{}}$

𝑥 − 1 ( 𝑥 − 3 ) 2 > 0 ${\displaystyle \frac{{}^{}x-1^{}}{{\left(x-3\right)}^2}>0}$

( 𝑥 − 1 ) ( 𝑥 − 3 ) > 0 ${\displaystyle \left(x-1\right)\left(x-3\right)>0^{}}$

𝑥 < 1 $x<1_{}^{}$

1 < 𝑥 < 3 $1<x<3$ или 𝑥 > 3 $x>3_{}^{}$

1 < 𝑥 < 3 $1<x<3_{}^{}$

𝑥 < 1 $x<1$ или 𝑥 > 3 $x>3_{}^{}$