Решите неравенство log 3 ( 1 𝑥 + 2 ) − log 3 ( 𝑥 + 5 ) ≥ log 3 ( 𝑥 + 4 𝑥 2 ) ${\displaystyle {\log }_3\left(\frac{1}{x}+2\right)-{\log }_3\left(x+5\right)\ge {\log }_3\left(\frac{x+4}{x^2}\right)}$ .