Решите неравенство log 5 ( 25 𝑥 ) log 5 𝑥 − 2 + log 5 𝑥 − 2 log 5 ( 25 𝑥 ) ≥ 6 − log 5 𝑥 4 log 2 5 𝑥 − 4 ${\displaystyle \frac{{\log }_5\left(25x\right)}{{\log }_{5}x-2}+\frac{{\log }_{5}x-2}{{\log }_5\left(25x\right)}\ge \frac{6-{\log }_5{x}^4}{{\log }_5^{2}x-4}}$ .