Решите неравенство 1 + 6 log 3 𝑥 − 3 + 5 log 2 3 𝑥 − log 3 ( 27 𝑥 6 ) + 12 ≥ 0 ${\displaystyle 1+\frac{6}{{\log }_{3}x-3}+\frac{5}{{\log }_3^{2}x-{\log }_3\left(27x^6\right)+12}\ge 0}$ .