Решите неравенство log 8 𝑥 log 8 ( 𝑥 64 ) ≥ 2 log 8 𝑥 + 3 log 2 8 𝑥 − log 8 𝑥 2 ${\displaystyle \frac{{\log }_{8}x}{{\log }_8\left(\frac{x}{64}\right)}\ge \frac{2}{{\log }_{8}x}+\frac{3}{{\log }_8^{2}x-{\log }_8{x}^2}}$ .