Решите неравенство log 2 32 𝑥 log 2 𝑥 − 5 + log 2 𝑥 − 5 log 2 32 𝑥 ≥ log 2 𝑥 16 + 18 log 2 2 𝑥 − 25 ${\displaystyle \frac{{\log }_{2}32x}{{\log }_{2}x-5}+\frac{{\log }_{2}x-5}{{\log }_{2}32x}\ge \frac{{\log }_2{x}^{16}+18}{{\log }_2^{2}x-25}}$ .