Решите неравенство 4 𝑥 − 3 ⋅ 2 𝑥 + 1 + 4 2 𝑥 − 5 + 3 ⋅ 2 𝑥 + 1 − 46 2 𝑥 − 8 ≤ 2 𝑥 + 5. $\frac{4^x\text{}-3\cdot 2^{x+1}+4}{2^x\text{}-5}+\frac{3\cdot 2^{x+1}-46}{2^x\text{}-8}\le 2^x+5.$