Решите неравенство log 5 ( ( 3 − 𝑥 ) ( 𝑥 2 + 2 ) ) ≥ log 5 ( 𝑥 2 − 7 𝑥 + 12 ) + log 5 ( 5 − 𝑥 ) ${\displaystyle {\log }_5\left(\left(3-x\right)\left(x^2+2\right)\right)\ge {\log }_5\left(x^2-7x+12\right)+{\log }_5\left(5-x\right)}$ .